An empty thick conducting shell of inner radi | vedclass

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Question

(D) $1$. When a conductor is earthed, its potential becomes zero. Since the shell is a conductor, the potential of the entire shell becomes zero.$2$.

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All of the above.

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(D) $1$. When a conductor is earthed, its potential becomes zero. Since the shell is a conductor, the potential of the entire shell becomes zero.$2$. The potential at the outer surface (radius $b$) is given by $V_b = k(Q_{in} + Q_{out})/b$. For $V_b = 0$, the total charge on the shell must be zero.$3$. Initially, the inner surface has charge $q_{in} = -4\pi a^2 \sigma$ and the outer surface has charge $q_{out} = 4\pi b^2 \sigma$.$4$. When the shell is earthed, the potential of the shell becomes zero. The charge on the inner surface remains $-q$ (due to induction from any internal charge), but the charge on the outer surface redistributes to make the total potential zero.$5$. Since the shell is earthed, electrons flow from the earth to the shell to neutralize the positive charge on the outer surface, making the outer surface charge zero. Thus, the potential of the entire shell becomes zero.

Column-$I$	Column-$II$
$(A)$ Ring along its axis	$(P)$ Graph with a peak at a distance $r > 0$
$(B)$ Uniformly charged solid sphere	$(Q)$ Graph increasing linearly for $r < R$ and decreasing as $1/r^2$ for $r > R$
$(C)$ Uniformly charged spherical shell	$(R)$ Graph with zero field for $r < R$ and decreasing as $1/r^2$ for $r > R$
$(D)$ Combination of charge $+Q$ and $-Q$ at the perpendicular bisector	$(S)$ Graph with a maximum at the center and decreasing as $r$ increases

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